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X^2=-3.8X
We move all terms to the left:
X^2-(-3.8X)=0
We get rid of parentheses
X^2+3.8X=0
a = 1; b = 3.8; c = 0;
Δ = b2-4ac
Δ = 3.82-4·1·0
Δ = 14.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.8)-\sqrt{14.44}}{2*1}=\frac{-3.8-\sqrt{14.44}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.8)+\sqrt{14.44}}{2*1}=\frac{-3.8+\sqrt{14.44}}{2} $
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